6k^2-19k+8=8

Solution for 6k^2-19k+8=8 equation:

6k^2-19k+8=8

We move all terms to the left:

6k^2-19k+8-(8)=0

We add all the numbers together, and all the variables

6k^2-19k=0

a = 6; b = -19; c = 0;
Δ = b2-4ac
Δ = -192-4·6·0
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{361}=19$
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-19)-19}{2*6}=\frac{0}{12}
=0
$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-19)+19}{2*6}=\frac{38}{12}
=3+1/6
$